This is a blog for my second semester pre-calculus 30s students. Have a blast!

Thursday, June 08, 2006

GO FOR GOLD ANSWER KEY!!!!!

MC:

1) D 2) A 3) D 4) C 5) B 6) B 7) C 8) A 9) A 10) B 11) C 12) C 13) A 14) B 15) B 16) D
17) C 18) C 19) A 20) D

SA:

1) a) 9x^2 - 6x + 3 b) 9x - 4

2) x = -2 (-7 is not a solution when checked)

3) AT = 5 cm; angle TRD = 90 deg.; TD = 10; arc RD = 90 deg.; angle CTS = 70 deg.

4) check your TI-83

5) a) (4, 1) b) x = 4 c) D = (-inf, +inf) R = (-inf, 1] d) x = 3, 5 e) check TI-83

6) f_inv = (x-3) / 2

7) ommitted

8) a) 87 mills b) $6525

9) C = (-4, 5) r = 11

10) a) in class b) 2 c) 2

11) theta = 80.4 deg, 279.6 deg

12) x = (7 +- root(57)) / 4

LA:

1) ... 3x^2 - 33x - 78 = 0
3(x - 13)(x + 2) = 0
x = 13 (-2 is an extraneous root)

2) (tan x - 3)(tan x + 2) = 0

x = 71.6 deg, 116.6 deg, 251.6 deg, 296.6 deg

3) a) x = 1; y = -1; z = -2
(1, -1, -2)

b) (+- 9/4, +- root(175/16))

4) [-1,5] .... number line as well.

5) b = 51.4, 5.4

6) > lengths of sides are equal. (dist. formula)
> opposite sides have equal slopes. (slope formula)
> diagonals bisect each other. (mid point formula)

7) f(1) = 0

therefore..(x-1) is a factor

...after synthetic division....(x-3) & (x-2) are other factors

...roots = 1,2,3, y-int = -6 graph as well

8) Sales: (6000 - 200; Profit: (20 + x)

Max = (6000 - 200x)(20 + x)
...
...
= -200x^2 + 2000x + 120000
* h = 5

P = 20 + 5
= $25.00

9) Assume 2 = 1; given 3 = 1
1 + 2 = angle ABC
3 + 4 = angle ACB
1 + 2 = 3 + 4

therefore: angle ABC = angle ACB

...but given ABC not = angle ACB

therefore 2 does not = 1

10) a) * shift 2 right, up 1 of y = 1/x; VA: x = 2; HA; y = 1; graph using TI-83

b) VA: x = 3, -3 HA: none; y-int: x = -1/9; sketch graph using TI-83

11) r = 7 using (distance from pt to line formula)
C = (1,5)

* therefore equation: (x - 1)^2 + (y - 5)^2 = 49

*

0 Comments:

Post a Comment

<< Home